How can three resistors of resistance 2Ω, 3Ω and 6Ωbe connected to give a total resistance of (i) 4Ω, (ii) 1Ω?
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ii) All the resistors can be connected in parallel
1/Rp= 1/2+1/3+1/6
1/Rp= 3+2+1/6
1/Rp= 6/6
Rp = 1Ω.
i) Resistor of 3Ω and 6Ω can be connected parallel and 2Ω in series.
1/Rp= 1/3+1/6
1/Rp= 2+1/6
1/Rp= 3/6
1/Rp= 1/2
Rp= 2Ω.
Reff= Rp+ Rs
Reff= 2+2
Reff= 4Ω.
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1/Rp= 1/2+1/3+1/6
1/Rp= 3+2+1/6
1/Rp= 6/6
Rp = 1Ω.
i) Resistor of 3Ω and 6Ω can be connected parallel and 2Ω in series.
1/Rp= 1/3+1/6
1/Rp= 2+1/6
1/Rp= 3/6
1/Rp= 1/2
Rp= 2Ω.
Reff= Rp+ Rs
Reff= 2+2
Reff= 4Ω.
Pls mark as brainliest if it helps you.
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for 1ohm resistor should be in parallel
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