How can three resistors of resistance 2, 3 and 6 ohm be connected to total resistance of 4 ohm & 1 ohm.
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There are three resistors of resistances 2 Ω, 3 Ω, and 6 Ω respectively. ... This equivalent resistor of resistance 2 Ω is connected to a 2 Ω resistor in series. Therefore, the equivalent resistance of the circuit = 2 Ω + 2 Ω = 4 Ω Hence the total resistance of the circuit is 4 Ω.
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I dont no sorry please like
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