How can u convert ethyl chloride to n butane
Answers
Answered by
0
C2H5Br+Mg→C2H5Mgcl;
C2H5mgcl+H(O=C)CH3→H3C−CH2CH(OH)
H3C−CH2CH(OH)CH3+Δ+H3PO4→butylene + water
butylene+H2(g)→n-butane
C2H5mgcl+H(O=C)CH3→H3C−CH2CH(OH)
H3C−CH2CH(OH)CH3+Δ+H3PO4→butylene + water
butylene+H2(g)→n-butane
Answered by
0
Since you're gonna need a four-carbon chain, you will need to alkylate the initial ethyl chloride.
Take a second equiv of ethyl chloride and hit it with Mg and a simple ether. The Mg will oxidatively insert between the 1-carbon and the Cl.
Next, the C--MgCl bond itself will attack the initial (first equiv) 1-carbon...this will eject the Cl off of the initial equiv via Sn2 mechanism.
And there you have it!
Hope this helps...
Take a second equiv of ethyl chloride and hit it with Mg and a simple ether. The Mg will oxidatively insert between the 1-carbon and the Cl.
Next, the C--MgCl bond itself will attack the initial (first equiv) 1-carbon...this will eject the Cl off of the initial equiv via Sn2 mechanism.
And there you have it!
Hope this helps...
Similar questions