Question

How can we calculate the number of base pair in E.coli if the length of DNA is 1.36nm?

Answer 1

Here, length of DNA is given as 1.36 nm and distance between 2 base pairs is 0.34 nm.

Therefore,

1.36 nm ÷ 0.34 nm = 4 base pairs.

Hope this helps you.

Answer 2

Distance between two consecutive base pair = 0.34 nm

Total length of given DNA = 1.36mm  

∴ total no. of base pair =  1.36mm /0.34nm

⇒ 4 × 10⁶ Base pair.