Question

how can we find the energy of big drops when small drops collapses??

Answer 1

mass of n particles added to make a big one
= mn
we can add there momentum

and there mass
but g acting on them is same

so potential energy of big drop = n m g h

and kinetic

m n gh.
because v = √ 2gh

when we put this value in
eq = 1/2 m v² we got
K.E =mngh

Answer 2

mass of n particles added to make a big one
= mn
we can add there momentum

and there mass
but g acting on them is same

so potential energy of big drop = n m g h

and kinetic

m n gh.
because v = √ 2gh

when we put this value in
eq = 1/2 m v² we got
K.E =mngh