Question

How can we find the nature of roots of a biqyadratic equation without actually solvibg it?

Answer 1

Answer:

D = ${b^2-4ac}$

Step-by-step explanation:

If a Quadratic polynomial of the form ${ax^2+bx+c = 0}$

Then, Discriminant(D) = ${b^2-4ac}$

If D = 0, then roots are real and equal

If D > 0 , then roots are real and distinct

If D <0 , then roots are not real.