how can we prove that if any triangle area's of 1/2 base. hight.. Its very urgent gyes?? Plz.. Fast...
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Answer:
Consider a rectangle ABCD ,It is divided into two congruent parts and that parts are triangles.
In the Rectangle, Length of AB=CD = a
Length of BC = DA = b
Now Area of Rectangle ABCD = AREA OF ABD + AREA OF CBD
AS BOTH TRIANGLES ARE CONGRUENT, THEIR AREAS ARE EQUAL .
Now, Area of Rectangle ABCD = 2( Area of triangle ABD)
We know that Area of rectangle = lb = a×b = ab .
Now From the relationship,
Area of triangle = ab/2 = 1/2 * base * height.
Hence proved!
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