Question

How can we prove that "In two concentric circles, such that a chord of the bigger circle, that touches the smaller circle is bisected at the point of contact with the smaller circle."

Answer 1

Let ' O ' be the common center of

two Concentric circles , and

Let AB be a chord of the larger circle

touching smaller circle touching the

smaller circle at P .

Join OP .

OP is the smaller circle radius and AB

is a tangent to this circle at a point P.

OP perpendicular to AB .

( We know that the perpendicular drawn

from the centre of a Circle to any chord

of the circle , bisects the chord . )

OP perpendicular to AB

=> AP = BP

Hence , AB is bisected at P .

I hope this helps you.

: )