Question

How can you u check whether 2/3and -1/2are the roots of 6x^2-x-2=0?​

Answer 1

Answer:

$6 {x}^{2} - x - 2 = 0 \\ factorise \\ 6 {x}^{2} - (4 - 3)x - 2 \\ 6 {x}^{2} - 4x + 3x - 2 \\ 2x(3x - 2) + 1(3x - 2) \\ (3x - 2)(2x + 1) = 0 \\ 3x - 2 = 0 \\ 3x = 2 \\ x = \frac{2}{3} \\ 2x + 1 = 0 \\ 2x = - 1 \\ x = \frac{ - 1}{2}$

♠Hope this may help you♠

Answer 2

Answer:

By putting them in the place of X

Step-by-step explanation:

Here correct method to check is

put the values in the equation and if you get answer as 0 then that is root of the equation..

In above case -

6x²-x-2=0(Given)

putting x=2/3

6×(2/3)²-2/3-2

6×4/9-2/3-2

8/3-2/3-2

6/3-2=0 (Hence 2/3 is root of the equation):Checked

now 6x²-x-2=0

putting x=-1/2

6×(-1/2)²-(-1/2)-2

6×1/4+1/2-2

3/2+1/2-2

4/2-2

2-2=0 (Hence -1/2 is root of the equation):checked

Hope it helps:-