How did he substitute a/a^1/3 in the equation?
Attachments:
Answers
Answered by
1
you can observe in snapshot below
ax/(ax)^1/3
(ax)^(1-1/3)
(ax)^(3-1/3)
(ax)^(2/3)
ax/(ax)^1/3
(ax)^(1-1/3)
(ax)^(3-1/3)
(ax)^(2/3)
Attachments:
Legend27:
So if denominator and numerator r same then it goes up and bevomes power minus
yes
Bases are same "ax"
Thanks
Similar questions