Math, asked by hijabzahra0, 1 year ago

how do i do this? Plz explain me

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Answered by bhupeshlodhi2003
1

Answer:


Step-by-step explanation:

Tan^3A / Sec^2A + Cot^3A / Cosec^2A 


= (sin^3A/cos^3A) / (1 / Cos^2A) + (Cos^3A/Sin^3A) / (1 / Sin^2A) 


= Sin^3A/CosA + Cos^3A/SinA 


= (Sin^4A + Cos^4A) / SinA.CosA 


= [ (Sin^2A + Cos^2A)^2 - 2Sin^2A.Cos^2A] / SinA.CosA 


= ( 1- 2Sin^A.Cos^A)/ SinA.CosA 


RHS = SecA CosecA - 2sinAcosA 


= 1/CosA . 1/SinA - 2SinACosA 


= (1 - Sin^2A.Cos^2A) / sinAcosA 


Hence LHS = RHS (PROVED)



Answered by angel8080
1
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