Question

How do I factor $12xy-4xz+z^2+4x^2+9y^2-6yz$ ?

Answer 1

Answer:

(2x+3y-z)(2x+3y-z)

Step-by-step explanation:

by formula (a+b+c)²=a²+b²+c²+2ab+2bc+2ac

So, 12xyz²-4xz+z²+4x²+9y²-6yz

=z²+4x²+9y²-6yz-4xz+12xy

=(-z)²+(2x)²+(3y)²+2*(-z)*3y+2*2x*(-z)+2*2x*3y

=(-z+2x+3y)²

=(2x+3y-z)(2x+3y-z)

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