Question

how do I factorise it?
how can I get a number so that when I add up I get -1 and when I multiply I get 10?

Answer 1

$3 {x}^{2} - x - 10 \\ \\ \\ = > 3 {x}^{2} - (6 - 5) - 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: | \bold{ \: 6 \times 5 = 3 \times 10 \: and \: 6 - 5 = 1} \\ \\ \\ = > 3 {x}^{2} - 6x + 5x - 10 \\ \\ \\ = > 3x(x - 2) + 5(x - 2) \\ \\ \\ = > ( x - 2)(3x + 5)$

Answer 2

here's your solution...hope it helps you:)