How do I find out what the pH of a solution made of 500ml 0.1M HCl and 500ml 0.1M NaOH is?
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No.of m. Equivalents of HCl =0.1x2x 500 =100
No.of m. Equivalents of NaOH =500x0.1= 50.
So 50 m. Equivalents of NaOH will react and neutralise 50 m. Moles of HCl and the resultant 1000 ml of the solution will contain (100–50)=50 m. moles of HCl.
The concentration of 1000 ml.of solution will be 100/1000=0.05N HCl.
The pH of this Solution= - log (0.05)=1.30(approx)
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