How do I find the answer?
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∫23√11xx2–1−−−−√dx∫1231xx2–1dx
=arcsecx∣∣∣23√1=arcsecx|123
=arcsec(23–√)−arcsec1=arcsec(23)−arcsec1
=arcsec(23–√)=arcsec(23)
=arcsecx∣∣∣23√1=arcsecx|123
=arcsec(23–√)−arcsec1=arcsec(23)−arcsec1
=arcsec(23–√)=arcsec(23)
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