how do I find the value of x
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2
Answer:
POQ+ROQ=180°(linear pair)
3x+2x=180°
5x=180°
x=180/5
x=36°
POQ =3×36= 108°
EOQ=2×36=72°
Answered by
1
Answer:
let 3x be 1st angle and 2x be 2nd angle
3x+2x = 180° ( liner pair)
5x = 180°
x = 180°/5
x= 36°
NOW,
First angle = 3x
= 3(36)
= 108°
Second angle = 2x
= 2(36)
= 72°
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