Question

How do I solve 0.9x^2-1.3x=0.8x-1

Answer 1

${0.9x}^{2} - 1.3x = 0.8x - 1 \\ \\ {0.9x}^{2} - 1.3x - 0.8x = -1 \\ \\ {0.9x}^{2} - 2.1x = - 1 \\ \\ {0.9x}^{2} - 2.1x + 1 = 0 \\ \\ {0.9x}^{2} + 1.5x + 0.6x + 1 = 0 \\ \\ 1.5x(0.6x+1) + 1(0.6x + 1) = 0 \\ \\ (0.6 + 1)(1.5x + 1) = 0$
Now,
$x = \frac{ - 1}{0.6} \: or \: \frac{ - 10}{6}$
Also,
$x = \frac{ - 1}{1.5} \: or \: \frac{ - 10}{15}$






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