Show that the triangle formed by vertices (-1,1),(7,5) and (9,1) is a right angle. Also find the length of the altitude corresponding to hypotenuse
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let a(-1,1),b(7,5),c(9,1) now for proving that the triangle made by these points is right triangle so u have to prove
hypotenuse ^2 =perpendicular^2 +base^2.....1st eq
firstly find the distance ab^2 by distance formula then similarly of bc^2 and ca^2
take the largest distance in lhs and both the smaller in rhs and put them in equation 1
if lhs =rhs then the triangle formed by these points is a right triangle
hope it helps!!!!
hypotenuse ^2 =perpendicular^2 +base^2.....1st eq
firstly find the distance ab^2 by distance formula then similarly of bc^2 and ca^2
take the largest distance in lhs and both the smaller in rhs and put them in equation 1
if lhs =rhs then the triangle formed by these points is a right triangle
hope it helps!!!!
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