How do I solve cos2x(2cosx+1)=0
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Answer:s=(1/2,π/3)
Step-by-step explanation:
cos2x(2cosx+1)=0
cos2x=0 or 2cosx +1 = 0
2x = cos0 and cosx = 1/2
x = cos0/2 and x = cos1/2
x = 1/2 and x = π/3
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Answer:
Explanation: Solving each part separately, cos(2x)=0or2cos(x)+1=0. Now, cos(2x)=0,0≤x≤2π Again,we have, 2cos(x)+1=0,0≤x≤2π cos(x)=−12: x=2π3+2πn, x=4π3+2πn.
Step-by-step explanation:
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