how do I solve:
x-2-(x-2)^2+ax-2a
Answers
Answered by
12
Take (x-2) as common
→ (x-2) - (x-2)^2 + ax - 2a=0
→ (x-2) [1 - (x-2)] + a(x-2)=0
→ (x-2) [1-x+2 +a]=0
→ -x +3+a=0
→ x=3+a
→ (x-2) - (x-2)^2 + ax - 2a=0
→ (x-2) [1 - (x-2)] + a(x-2)=0
→ (x-2) [1-x+2 +a]=0
→ -x +3+a=0
→ x=3+a
goldencuber:
thanks, bou I had to factorize it so the ans is till 3rd line.
but*
Answered by
5
Hiiii,
x-2-(x-2)^2+ax-2a
▪x-2-(x-2)^2+ax-2a=0
▪Take common :
(x-2){1-(x-2)} +a(x-2)=0
▪(x-2)(1-x-2+a)=0
▪-x+3+a =0
▪x=3+a
HOPE IT WILL HELP U..
PLZ MARK IT AS BRAINLIEST ANSWER...
x-2-(x-2)^2+ax-2a
▪x-2-(x-2)^2+ax-2a=0
▪Take common :
(x-2){1-(x-2)} +a(x-2)=0
▪(x-2)(1-x-2+a)=0
▪-x+3+a =0
▪x=3+a
HOPE IT WILL HELP U..
PLZ MARK IT AS BRAINLIEST ANSWER...
thanks.
welcome
: )
lol, the process had to be same.
Similar questions