Physics, asked by sahusushmita744, 4 months ago

How do R, XL and XC get affected when the frequency of applied AC is doubled?​

Answers

Answered by Anonymous
1

Answer:

You need to understand how frequency affects inductive reactance and a capacitive reactance. As the reactance of a device increases, its impedance increases.

A general statement is inductors offer a lower reactance to lower frequencies and a higher reactance to higher frequencies. The specific relationship between frequency and XL is expressed by this equation:

XL = 2 x pi x f x L.

You can see that XL increases as f increases.

A general statement is capacitors offer a lower reactance to higher frequencies and a higher reactance to lower frequencies. The specific relationship between frequency and XC is expressed by this equation:

XC = 1/(2 x pi x f x C).

You can see that XC decreases as f increases.

I suggest assigning values for f, L and C and calculate XL and XC. Then double the value of f, recalculate both and you will have your answer.

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