Question

How do we find (a+b+c) when (a^2+b^2*c^2) is given=125 and (ab+bc+ca)= 50

Answer 1

Step-by-step explanation:

I don't have any answer of this question

Answer 2

Step-by-step explanation:

There may be some mistake in the question.. Instead of (a+b+c), it may be = a² + b² + c²

There is no such Identity that can solve that question. In cube identity it is there. But not In square

By using Identity - (a²+ b²+ c²) = a² + b² + c² + 2(ab+bc+ca)

(a²+b²+c²) is given = 125

(ab+bc+ca) is also given = 50

Therefore,

125 = a²+b²+c² +2(50)

125 = a²+b²+c² +100

(Shift 100 to Left side)

125 + 100 = a²+b²+c²

225=a²+b²+c²

This is not required answer because there is no square identity that can solve this