How do we find the oxidation no of carbon in ethanol?
Answers
Answered by
0
Ethanol-
C2H5OH
2x+(1×5)+(-2)+1=0
2x+5-2+1=0
2x+4=0
X=-4/2
X=-2
C2H5OH
2x+(1×5)+(-2)+1=0
2x+5-2+1=0
2x+4=0
X=-4/2
X=-2
Similar questions