How do we find the solubility of magnesium hydroxide in water in terms of Ksp?
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Answer:
We interrogate the equilibrium..........and get,
S
=
2.32
×
10
−
4
⋅
m
o
l
⋅
L
−
1
Explanation:
We interrogate the equilibrium..........
M
g
(
O
H
)
2
(
s
)
⇌
M
g
2
+
+
2
H
O
−
And
K
sp
=
[
M
g
2
+
]
[
−
O
H
]
2
And now if we call the solubility of
M
g
(
O
H
)
2
S
, then by definition,
S
=
[
M
g
2
+
]
, and
2
S
=
−
O
H
.
And thus
K
sp
=
S
×
(
2
S
)
2
=
4
S
3
And so (finally!),
S
=
3
√
K
sp
4
S
=
3
√
5.0
×
10
−
11
4
=
2.32
×
10
−
4
⋅
m
o
l
⋅
L
−
1
And of course we can convert this to a
mass solubility
, by multiplying
S
by the molar mass..........i.e.
58.32
⋅
g
⋅
m
o
l
−
1
×
2.32
×
10
−
4
⋅
m
o
l
⋅
L
−
1
=
1.35
×
10
−
2
⋅
g
⋅
L
−
1
.
What is the
p
H
of a saturated solution? This is a common follow up question.
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