how do we solve the HCF by division method
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We divide the bigger number by smaller one.Divide smaller number in step 1 with remainder obtained in step 1.Divide divisor of second step with remainder obtained in step 2.We will continue this process till we get remainder zero and divisor obtained in end is the required H.C.F...
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Go on solving it, when the reminder becomes Zero, the Divider will be the HCF , for example:
Let's take two numbers , say 2 and 4
According to a = bq + r
4 = 2×2+0
so , HCF = 2
Let's take two numbers , say 2 and 4
According to a = bq + r
4 = 2×2+0
so , HCF = 2
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