Question

how do we solve this?
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Answer 1

Answer:

hope it helps you see the attachment for further information ...✌✌✌

Answer 2

Answer:

Consider Everytime the differences pairwise in [A] and the time intervals.

So,

1) At first Rate of reaction= 18-20/5-0 = -2/5 mol/L min^-1

Now,

2) Rate of reaction = 16-18/10-5 = -2/5

and, so on it can be clearly seen that the rate of the reaction remains constant also for other intervals.

Clearly, this means that for every 5 minutes, 2 moles of A will decrease.

So,

at 20 minutes, there will remain just 12 moles of A, however clearly the rate will still remains 2/5 that is 0.4 only !

So, option D is correct here.

This also tells us that since the rate remains constant and doesn't depends on the concentration of A , it means the reaction in which A is involved as the reactant, the reaction is a zero order reaction.