Math, asked by harikkarnati5329, 1 year ago

How do you add (−7+7i)+(6−2i) in trigonometric form?

Answers

Answered by anooproy2004

0

Answer:

(-7+7i)+(6-2i)=0

-7+7i+6-2i=0

-7+6+7i-2i=0

-1+5i=0

-1=-5i

i=1/5

Step-by-step explanation:

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