Question

Radius of a bubble at the bottom of the tank
shown below was found to be 1 cm. Findthe radius of the bubble(in cm) at the
surroundingface of water at same temperature.
Pressure at bottom =
height of the container.in both sides is 10.336m
if any one type some thing instead of answer they are idots
please give me reply quickly​

Answer 1

ANSWER

P1

=1atm at surface

V

1

=Volume at Surface

P

2

= Pressure at bottom

h = depth of the lake

ρ=density of water

If temperature is same, P

1

V

1

=P

2

V

2

1⋅V

1

=(1 + h ρ g )V

2

⇒V

1

=(1 + h ρ g)

3

4

πr

2

3

V

1

=(1 + h ρ g)

3

4

π1

3

⇒

3

4

πr

1

3

=

3

4

π(1 + h ρ g)

⇒r

1

=(31+hρg)cm

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Answer 2

Answer:

P

1

=1atm at surface

V

1

=Volume at Surface

P

2

= Pressure at bottom

h = depth of the lake

ρ=density of water

If temperature is same, P

1

V

1

=P

2

V

2

1⋅V

1

=(1 + h ρ g )V

2

⇒V

1

=(1 + h ρ g)

3

4

πr

2

3

V

1

=(1 + h ρ g)

3

4

π1

3

⇒

3

4

πr

1

3

=

3

4

π(1 + h ρ g)

⇒r

1

=(

3

1+hρg

)cm

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