How do you differentiate ln∣∣cosxcosx−1∣∣?
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0
Answer:
d
d
x
[
ln
∣
∣
cos
x
cos
x
−
1
∣
∣
]
=
0
Explanation:
We're asked to find the derivative
d
d
x
[
ln
∣
∣
cos
x
cos
x
−
1
∣
∣
]
The value
cos
x
cos
x
=
1
:
d
d
x
[
ln
|
1
−
1
|
d
d
x
[
ln
|
0
|
]
The natural logarithm of
0
is
−
∞
:
d
d
x
[
−
∞
]
The derivative of negative infinity (a constant) is
0
:
d
d
x
[
ln
∣
∣
cos
x
cos
x
−
1
∣
∣
]
=
0
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