Math, asked by arindam999, 9 months ago

How do you differentiate sin^3x?

Answers

Answered by HirakRaza

0

Step-by-step explanation:

3sin^2xcosx

this is the deferential

Answered by tyagidipanshu098

0

Answer:

-3cosx+(cos3x)/3

Step-by-step explanation:

sin^3x= 3sinx-sin3x

in(sin^3x)=in(3sinx-sin3x)

=in(3sinx)-in(sin3x)

= -3cosx+(cos3x)/3 .ans

sorry i integrate it.

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