How do you differentiate sin^3x?
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Answered by
0
Step-by-step explanation:
3sin^2xcosx
this is the deferential
Answered by
0
Answer:
-3cosx+(cos3x)/3
Step-by-step explanation:
sin^3x= 3sinx-sin3x
in(sin^3x)=in(3sinx-sin3x)
=in(3sinx)-in(sin3x)
= -3cosx+(cos3x)/3 .ans
sorry i integrate it.
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