Question

How do you evaluate 1(x2)⋅(x2+4)12?

Answer 1

Question: How do you evaluate 1(x2)⋅(x2+4)12?

Answer :

$12x {}^{4} + 48x {}^{2}$

Step by step explanation :

$1(x {}^{2} ) \times (x {}^{2} + 4)12$

Any expression multiplied by 1, remains the same.

$= > x {}^{2} \times (x {}^{2} + 4) \times 12$

Use the commutative property to reorder the terms

$= > 12x {}^{2} \times (x {}^{2} + 4)$

Distribute 12x^2 through the parenthesis. Multiply each term in the parenthesis by 12x^2

$= > 12x {}^{2} \times x {}^{2} + 12x {}^{2} \times 4$

Calculate the product

$= > 12x {}^{4} + 12x {}^{2} \times 4$

Calculate the product

$= > 12x {}^{4} +48x {}^{2}$

Answer 2

Step-by-step explanation:

1(x^2)* (x^2+4) * 12

Any number multiplied by 1 remains same

➡️ Therefore 1* (x^2)= x^2

Multiply all numbers except the number the bracket

=(12* x^2)(x^2+4)

=12x^2 * (x^2+4)

=12x^4 + 48x^2

Note: You can also use distributive property

=(12* x^2)(x^2+4)

=12x^2 * (x^2+4)

=(12x^2* x^2)+ (12x^2* 4)

=12x^4 + 48x^2