How do you evaluate ddx∫x4x√t2+tdt?
brunoconti:
not clear. send a pic instead
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Answer:
ddx(y^2 divided by 2 + 16x^2 y^3/2 divided by 3 +c)
Step-by-step explanation:
∫ x * 4x√y * 2 + ydy= y^2 divided by 2 + 16x^2 y^3/2 divided by 3 +c
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