Math, asked by ramkumar3419, 1 year ago

How do you evaluate ddx∫x4x√t2+tdt?


brunoconti: not clear. send a pic instead
Anonymous: ___k off

Answers

Answered by TheTheyLoveKeke
0

Answer:

ddx(y^2 divided by 2 + 16x^2 y^3/2 divided by 3 +c)

Step-by-step explanation:

∫ x * 4x√y * 2 + ydy= y^2 divided by 2 + 16x^2 y^3/2 divided by 3 +c

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