How do you evaluate f(0) given the function f(x)=5(2−x)11?
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f(x)=5(2-x)11
put f(x)=f(0)
f(0)=5(2-0)×11
f(0)=5×2×11
f(0)=110
put f(x)=f(0)
f(0)=5(2-0)×11
f(0)=5×2×11
f(0)=110
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