Math, asked by sriramsri620, 1 year ago

How do you factor 6r + 8- r + 8r + 9r ^ { 2} + 3?

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

6r + 8- r + 8r + 9r ^ { 2} + 3

=9r²+13r+11

here a=9,b=13,c=11

discrimination D=b²-4ac=13²-4(9)(11)

=169-396= -227

so r=1/18[-13±√-227]

r=-13/18±√-227/18

r=-13/18±i√227/18  ( here i=√-1)

r+13/18+i√227/18 and r+13/18-i√227/18

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