Question

How do you factor 9(x+2y+z)2−16(x−2y+z)2?

Answer 1

$= 18(x + 2y + z) - 32(x - 2y + z) \\ = 18x + 36y + 18z - 32x + 64y - 32z \\ = -14x + 100y - 14z \\ = - 2(7x - 50y + 7z)$

Answer 2

$9 \times 2(x + 2y + z) - 16 \times 2(x - 2y + z) \\ 18(x + 2y + z) - 32(x - 2y + z) \\ 18x + 36y + 18z - 32x - 64y + 32z \\ 14x - 28y + 50z \\ \\ \\ solved \alpha \beta \gamma$