How do you factor 9z^2 + 6z - 8?
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Answered by
0
Answer:
Step-by-step explanation:
9z²+6z-8 = 0
9z²+12z-6z-8 = 0
3z(3z+4) - 2(3z+4) = 0
(3z+4) (3z-2) = 0
z = -4/3 or z = 2/3
Answered by
1
9z^2+6z-8
=9z^2+12z-6z-8
=3z(3z+4)-2(3z+4)
=(3z-2)(3z+4)
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