Question

How many grams of carbon monoxide can you produce from 3 grams of carbon and an excess of oxygen?

Answer 1

About

7

g

of

C

O

,

Explanation:

We need (i) a stoichiometric equation:

C

(

s

)

+

1

2

O

2

(

g

)

→

C

O

(

g

)

And now (ii) we need the equivalent quantity of

C

.

Moles of carbon

=

3.0

⋅

g

12.011

⋅

g

⋅

m

o

l

−

1

=

1

4

⋅

mole

.

So mass of carbon monoxide

=

1

4

⋅

m

o

l

×

28

⋅

g

⋅

m

o

l

−

1

=

7

⋅

g

.