Question

How do you factor f3+2f2−64f−128?

Answer 1

Answer :

$(f + 2) \times (f - 8) \times (f + 8)$

Step by step explanation :

$f {}^{3} + 2f {}^{2} - 64f - 128$

Factor out f^2 from the expression

$= > f {}^{2} \times (f + 2) - 64f - 128$

Factor out - 64 from the expression.

$= > f {}^{2} \times (f + 2) - 64(f + 2)$

Factor out f + 2 from the expression

$= > (f + 2) \times (f {}^{2} - 64)$

Write the number 64 in exponential form with an exponent of 2.

$= > (f + 2) \times (f {}^{2} - 8 {}^{2} )$

Using

$a {}^{2} - b {}^{2} = (a - b)(a + b)$

, factor the expression

$= > (f + 2) \times (f - 8) \times (f + 8)$