How do you find the sum or difference of (g3−2g2+5g+6)−(g2+2g)?
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Answered by
5
Answer:
Step-by-step explanation:
(g³ - 2g² + 5g +6 ) -(g² + 2g)
G³ - 2g² + 5g + 6 - g² - 2g
G³ - 2g² - g² + 5g - 2g + 6
G³ - 3g² + 3g + 6
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Answered by
0
HEY MATE HERE IS YOUR ANSWER--
=)(g³-2g+5g+6)-(g²+2g)
=)g³-2g+5g+6-g²-2g
¶[[g³-3g²+3g+6]]¶
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