How do you factor (r+s)(s+t)-(r+s)(s-t)+(r+s)(s+t)?
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Answered by
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Solution:
(r+s)(s+t)-(r+s)(s-t)+(r+s)(s+t)
Take (r+s) common, we get
= (r+s)[s+t-(s-t)+s+t]
= (r+s)[s+t-s+t+s+t]
=(r+s)(3t+s)
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Hey !
Refer the below attachment!
Thanks!
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