Question

How do you factor −x2+15x−50=0?

Answer 1

we can write it as

x2-15x+50 = 0;

x2-5x-10x+50 = 0;

let x and 10 as common

x(x-5)-10(x-5) = 0;

(x-5) (x-10) = 0;

now equating both terms we get;

X = 5 and x = 10

Answer 2

Answer:

$- {x}^{2} + 15x - 50 = 0 \\ ( - {x}^{2} + 15x - 50 = 0) \times - 1 \\ = {x}^{2} - 15x + 50 = 0 \\ \\ {x}^{2} - 15x + 50 = 0 \\ {x}^{2} - 10x - 5x + 50 = 0 \\ x(x - 10) - 5(x - 10) = 0 \\ (x - 10)(x - 5) = 0 \\ x - 10 = 0 \: \: \: or \: \: \: x - 5 = 0 \\ x = \underline{ \underline{ 10}} \: \: \: or \: \: \: x = \underline{ \underline{ 5}}$