Question

How do you factor x3y−x2y2−20xy3 completely?

Answer 1

Answer:

Step-by-step explanation:

x³y−x²y²−20xy³

=xy(x²-xy-20y²)

If we multiply the coefficient x² and y²

that is 1(-20)=-20

so we have to choose factor of 20 so that difference is equal to -1

we know that 5-4=1 and 5*4=20 ,so no are 5 and 4

so factors are

=xy((x²-5xy+4xy-20y²)

=xy[x(x-5y)+4y(x-5y)]

=xy(x-5y)(x+4y)