How do you factor y2−2y−3?
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Solution:
Given Quadratic expression:
y²-2y-3
Splitting the middle term, we get
= y²-3y+1y-3
= y(y-3)+1(y-3)
= (y-3)(y+1)
Therefore,
y²-2y-3 = (y-3)(y+1)
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Answered by
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Hey !
Refer the below attachment !
Thanks !
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