Question

How do you factor y3−18y2+81y?

Answer 1

Solution:

y³-18y²+81y

Take y common in each term, we get

= y(y²-18y+81)

=y( y²-9y-9y+81)

= y[ y(y-9)-9(y-9)]

= y(y-9)(y-9)

Therefore,

y³-18y²+81y = y(y-9)(y-9)

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Answer 2

Hey !

Refer the below attachment !

Thanks!