Question

How do you factorise -4ab-20ac+6abc?

Answer 1

Using a

3

+b

3

+c

3

−3abc=

2

1

(a+b+c)[(a−b)

2

+(b−c)

2

+(c−a)

2

]

We can rewrite, a

3

+8b

3

+c

3

−6abc as,

=

2

1

(a+2b+c)[(a−2b)

2

+(2b−c)

2

+(c−a)

2

]

Hence, the answer is

2

1

(a+2b+c)[(a−2b)

2

+(2b−c)

2

+(c−a)

2

].

this is answer

Answer 2

HERE IS THE ANSWER

$\begin{gathered}6abc - 9 {a}^{2}c \\ = 3ac(2b - 3a) \end{gathered}6abc−9a2c=3ac(2b−3a)$