Question

How do you find 2 sqrt 325?

Answer 1

Answer : 10√13

Step by step explanation :

$2 \sqrt{325}$

Factor out the perfect square

$= > 2 \sqrt{5 {}^{2} \times 13 }$

The root of a product is equal to the product of the roots of each factor

$= > 2 \sqrt{5 {}^{2} } \sqrt{13}$

Reduce the index of the radical and exponent with 2

$= > 2 \times |5| \sqrt{13}$

The absolute value of any number is always positive.

$= > 2 \times 5 \sqrt{13}$

Calculate the product by multiplying the numbers

$= > 10 \sqrt{13}$

ALTERNATIVE FORM

$36.05551$

Answer 2

$\large{\mathfrak{\underline{\underline{Answer:}}}}$

$\sf 2 \sqrt{325} = 10 \sqrt{13}$

But, The perfect value is 36.05551.

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$\large{\mathfrak{\underline{\underline{Solution:}}}}$

$\sf{LCM \: of \: 325 = 5 × 5 × 13} \\ \\ \textsf{So,} \\ \sf \sqrt{325} = \sqrt{5^{2} \times 13} \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: = 5\sqrt{13} \\ \\ \sf 2 \sqrt{325} = 2 \times 5\sqrt{13} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sf 10 \sqrt{13} \\ \\ \sf \large{\underline{ \underline{ Hence \: Proved!!!!!! }}}$

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