How do you find a polynomial of degree 3 that has zeros of -3, 0, 1?
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sum of zeroes = a + b +c
= (-3)+ 0+ 1=-2
product of zeroes taken as two at a time = ab + bc + ca
=(-3)0 + (-3)1+ 1×0=-3
product of zeroes = ABC
= (-3)1×0 =0
polynomial in 3 degree is
x ^3 - (sum of zeroes)x^2 + (product of zeroes taken 2 at a time)x - product of zeroes
therefore polynomial is
x^3 + 2x^2 -3x
Hope will help
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= (-3)+ 0+ 1=-2
product of zeroes taken as two at a time = ab + bc + ca
=(-3)0 + (-3)1+ 1×0=-3
product of zeroes = ABC
= (-3)1×0 =0
polynomial in 3 degree is
x ^3 - (sum of zeroes)x^2 + (product of zeroes taken 2 at a time)x - product of zeroes
therefore polynomial is
x^3 + 2x^2 -3x
Hope will help
plz mark as brainliest...
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