how do you find distance travelled by a particle in time travelled by a particle in time between 0 and 10 seconds in a vt graph?
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the area under velocity time graph gives displacement. Now if we add area in negative y axis then it will give distance hence
distance=4×10×0.5+2×10×0.5+4×0.5×5
=40m
distance=4×10×0.5+2×10×0.5+4×0.5×5
=40m
rin35:
thanks a lot!It really helped!
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