Math, asked by NubrincePlaysGt, 3 months ago

How do you find the area of this obtuse triangle?

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Answers

Answered by Saby123
9

Solution :

To find the area of ∆ABC , you can find the areas of ∆ADC and ∆CDB and then subtract the values.

Alternatively you can apply the sine rule

In triangle ADC

It's right angled

AC² = AD² + DC²

> 144 = (6+BD)² + 16

> (BD + 6)² = 128

> BD + 6 = |√128|

> BD = 8√2 - 6 units

AD = 6 + (8√2-6) = 8√2 units

Area of ∆ADC

> ½ × 8√2 × 4

> 16√2

Area of ∆BDC

> ½ × 4 × (8√2-6)

> 2(8√2-6)

> 16√2 - 12

Area of ∆ABC

>> 16√2 - (16√2-12)

>> 12 unit²

Answer : The area of the obtuse triangle ABC is 126 unit² .

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Answered by HarshitJaiswal2534
0

Step-by-step explanation:

Solution :

To find the area of ∆ABC , you can find the areas of ∆ADC and ∆CDB and then subtract the values.

Alternatively you can apply the sine rule

In triangle ADC

It's right angled

AC² = AD² + DC²

> 144 = (6+BD)² + 16

> (BD + 6)² = 128

> BD + 6 = |√128|

> BD = 8√2 - 6 units

AD = 6 + (8√2-6) = 8√2 units

Area of ∆ADC

> ½ × 8√2 × 4

> 16√2

Area of ∆BDC

> ½ × 4 × (8√2-6)

> 2(8√2-6)

> 16√2 - 12

Area of ∆ABC

>> 16√2 - (16√2-12)

>> 12 unit²

Answer : The area of the obtuse triangle ABC is 126 unit² .

________________________________________

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