How do you find the day of a particular date without calendar?
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MONTH CODES:
January: 1
Feb : 4
march :4
april : 0
may :2
june : 5
july :0
august :3
sept :6
oct : 1
november :4
december : 6.
CENTURY CODES:
1500-1599 : 0
1600-1699 : 6
1700-1799 : 4
1800-1899 : 2
1900-1999 : 0
2000-2099 :6.
DATE CODES:
sat - 0
sunday - 1
monday- 2
tues - 3
wed - 4
thur - 5
fri - 6.
FORMULA :
DATE+month code+no.of leap years +year+century code.
eg: 4th july 1988 which day?
4+5+22 (for leap years you have to divide last 2 digits of year with 4 and you have to write quotient but not in decimal form. you can leave remainder.)+ 88 (you have to write last two digits of that year)+0.
= 31.
now, you have to divide with 7 as weak has 7 days.
you will get remainder 2. so according to day code 2 is monday.
January: 1
Feb : 4
march :4
april : 0
may :2
june : 5
july :0
august :3
sept :6
oct : 1
november :4
december : 6.
CENTURY CODES:
1500-1599 : 0
1600-1699 : 6
1700-1799 : 4
1800-1899 : 2
1900-1999 : 0
2000-2099 :6.
DATE CODES:
sat - 0
sunday - 1
monday- 2
tues - 3
wed - 4
thur - 5
fri - 6.
FORMULA :
DATE+month code+no.of leap years +year+century code.
eg: 4th july 1988 which day?
4+5+22 (for leap years you have to divide last 2 digits of year with 4 and you have to write quotient but not in decimal form. you can leave remainder.)+ 88 (you have to write last two digits of that year)+0.
= 31.
now, you have to divide with 7 as weak has 7 days.
you will get remainder 2. so according to day code 2 is monday.
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